subspace oor Sjinees

subspace

naamwoord
en
(mathematics) A subset of a space which is a space in its own right.

Vertalings in die woordeboek Engels - Sjinees

子空间

naamwoord
More importantly, the new detectors are robust of the rank selection of the clutter subspace compared to the reduced-rank AMF and GLRT.
更重要的是, 新检测器对杂波子空间秩的选取不敏感。
GlosbeMT_RnD

Geskatte vertalings

Vertoon algoritmies gegenereerde vertalings

SubSpace

en
SubSpace (computer game)

Vertalings in die woordeboek Engels - Sjinees

Geen vertalings nie

Soortgelyke frases

linear subspace
线性子空间

voorbeelde

Advanced filtering
Voorbeelde moet herlaai word.
Admiral Hanson on subspace, Captain.
這 關 係 到 所有 依靠 著 我們 的 人 家有 口 的 人OpenSubtitles2018.v3 OpenSubtitles2018.v3
Since every subspace is contained in the next subspace, the residual does not increase.
喔 喲 為 什 么 我 穿著 這些 破衣服 ?WikiMatrix WikiMatrix
A new verification of the equivalence of two well-known methods in the Krylov subspace, namely the multistage Wiener filters (MWF) and the auxiliary-vector filtering (AVF), is given in this paper.
允许用不信任的密钥加密springer springer
Then W is a subspace of R2.
真的? 吗 我?? 还 真 像- 我 想 是的LASER-wikipedia2 LASER-wikipedia2
Put a repeating message on all subspace channels.
只 是? 举 行 婚? 礼 , 不要 太?? 张OpenSubtitles2018.v3 OpenSubtitles2018.v3
Theorem 1: The subspace spanned by a non-empty subset S of a vector space V is the set of all linear combinations of vectors in S. This theorem is so well known that at times it is referred to as the definition of span of a set.
對, 我 對 造成 的 不便 很 抱歉LASER-wikipedia2 LASER-wikipedia2
If V is a normed vector space with linear subspace U (not necessarily closed) and if z is an element of V not in the closure of U, then there exists a continuous linear map ψ : V → K with ψ(x) = 0 for all x in U, ψ(z) = 1, and ||ψ|| = dist(z, U)−1.
我? 们 在做 什 么. 我? 们 得出 去LASER-wikipedia2 LASER-wikipedia2
The map from X to its image in βX is a homeomorphism to an open subspace if and only if X is locally compact Hausdorff.
然后 你 發現 沒有 人 比她 好LASER-wikipedia2 LASER-wikipedia2
The theorem has several important consequences, some of which are also sometimes called "Hahn–Banach theorem": If V is a normed vector space with linear subspace U (not necessarily closed) and if φ : U → K is continuous and linear, then there exists an extension ψ : V → K of φ which is also continuous and linear and which has the same norm as φ (see Banach space for a discussion of the norm of a linear map).
你 要 我? 们 根 据 你的 直? 觉 ...花?? 数 百 万 元?? 整??? 队 ?LASER-wikipedia2 LASER-wikipedia2
Conversely, if f is also an inclusion the attaching construction is to simply glue X and Y together along their common subspace.
前款 规定 的 证券 服务 机构 及其 从业 人员 所 制作, 出具 的 文件 存在 虚假 记载, 误导性 陈述 或者 重大 遗漏 的, 责令 改正, 依照 证券法 第二百二十三 条 予以 处罚; 情节 严重 的, 可以 采取 市场 禁入 的 措施; 涉嫌 犯罪 的, 依法 移送 司法 机关 追究 刑事 责任LASER-wikipedia2 LASER-wikipedia2
The corresponding Krylov subspace method is the minimal residual method (MinRes) of Paige and Saunders.
什 么 叫 “ 就 这么看着你”? 么 看? 你 ”?WikiMatrix WikiMatrix
In the case where A is a closed subspace of Y one can show that the map X → X ∪f Y is a closed embedding and (Y − A) → X ∪f Y is an open embedding.
你??? 该 想睡? 觉 了吧, 我? 带 你? 们 去看? 卧 房LASER-wikipedia2 LASER-wikipedia2
Natural scenes form a tiny subspace in the space of all possible signals, and researchers have developed sophisticated models to characterize these statistics.
你 彈 得 比 我 好 , 還 希望 自己 作曲LASER-wikipedia2 LASER-wikipedia2
It allows the extension of bounded linear functionals defined on a subspace of some vector space to the whole space, and it also shows that there are "enough" continuous linear functionals defined on every normed vector space to make the study of the dual space "interesting".
容 格 夫人, 我?? 识 他 ,...我 丈夫 , 已?# # 年 了LASER-wikipedia2 LASER-wikipedia2
Suppose that (V, q) is quadratic space and W is a subspace.
迅速让头两个敌人落到两个水泥块上面的格子里, 然后马上从左边放走他们 。 然后迅速向右走, 落到正在下落的第三个敌人的头上。 踩着他的头登上梯子 。LASER-wikipedia2 LASER-wikipedia2
However, that PCA is a useful relaxation of k-means clustering was not a new result (see, for example,), and it is straightforward to uncover counterexamples to the statement that the cluster centroid subspace is spanned by the principal directions.
那 艘 船 應該 不會 靠岸 的WikiMatrix WikiMatrix
Suppose we have a path-connected space X, covered by path-connected open subspaces A and B whose intersection D is also path-connected.
讓 我們 把 事情 說 清楚 一點 可以 吧WikiMatrix WikiMatrix
Since every subspace of a compact Hausdorff space is Tychonoff one has: A topological space is Tychonoff if and only if it can be embedded in a Tychonoff cube.
? 为 什 么 ?- 我? 让 那 孩子 成了 英雄LASER-wikipedia2 LASER-wikipedia2
Within this the other nationally based initiatives, including the poverty reduction strategy papers, the national human development reports and the United Nations Development Assistance Framework, can fit perfectly well for these will cover a particular subspace of the goals
我 不 打算? 过 去了-? 为 什 么 ?MultiUn MultiUn
More importantly, the new detectors are robust of the rank selection of the clutter subspace compared to the reduced-rank AMF and GLRT.
你??? 过 火? 车 的.- 我? 从 天上? 飞 回去springer springer
For Banach spaces, a one-dimensional subspace always has a closed complementary subspace.
好吧 , 但 你 不能 就 這樣 ...洗手 不 幹 了LASER-wikipedia2 LASER-wikipedia2
(In order to do this, we have to translate the geometrical tangent space to M so that it passes through the origin rather than x, and hence defines a k-dimensional vector subspace.
哇 , 到底 是 怎 么 回事我 都 听 到了? 这 些LASER-wikipedia2 LASER-wikipedia2
Two vectors of Rn are in the same congruence class modulo the subspace if and only if they are identical in the last n−m coordinates.
她 結束 高中生 涯 的時候 為 什 么 要 和 我 在一起?LASER-wikipedia2 LASER-wikipedia2
A way to characterize subspaces is that they are closed under linear combinations.
嗨 ,? 汤 姆- 我? 们 要 把 你 到 床上 去LASER-wikipedia2 LASER-wikipedia2
Then W is a subspace of V. Proof: Given u and v in W, then they can be expressed as u = (u1, u2, 0) and v = (v1, v2, 0).
你? 们 要求 我? 们 像? 个 盟? 国 一?? 帮 你? 们我? 们 也 要求 你? 们 把 我?? 当 盟? 国 一?? 对 待LASER-wikipedia2 LASER-wikipedia2
70 sinne gevind in 4 ms. Hulle kom uit baie bronne en word nie nagegaan nie.