Besonderhede van voorbeeld: 1689726987013912003

English

The probability of observing an absolute difference from the mean midrank that exceeds the absolute value of S minus the mean of the midranks is 0.0005.

Chinese

观测到与中秩均值的绝对差值超过 S 减去中秩均值后的绝对值的概率为 0.0005。