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English[en]
Well, the points M and N lie on the circle with diameter BC, and the center of this circle is obviously the midpoint O of BC. Thus, MO = NO, so that the triangle MON is isosceles, and hence the line OR, being the angle bisector of the angle MON, coincides with the perpendicular bisector of the segment MN. Hence, the point R lies on the perpendicular bisector of the segment MN.
Tagalog[tl]
Balon, ang mga puntos sa M at N kasinungalingan sa bilog na may diameter BC, at ang gitna ng bilog na ito ay malinaw naman ang midpoint O ng BC. Kaya, MO = NO, kaya na ang tatsulok ay MON isosceles, at kaya ang linya O, pagiging anggulo panggitnang guhit ng MON anggulo, coincides sa panggitnang guhit patayo ng MN segment.

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