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English[en]
Because p(x) has degree 3, if it is reducible over by Q then it has a rational root. By the rational root theorem, this root must be 1 or −1, but both are clearly not roots.
Spanish[es]
Si ese polinomio pudiera reducirse a grado 2, tendría una raíz racional, que por el teorema de la raíz racional, debería ser 1 o −1, que evidentemente no son raíces.

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